：1、y²-1分之4加1-y分之y-3加1=0 2、x-3分之1减x-4分之1=x-6分之1减x-7分之1

⊙_⊙沫 2023-03-17 08:51

• 

  ___一休___

  2023-03-17 09:08

  1,4/(y²-1)+(y-3)/(1-y)+1=0

  4-(y-3)(y+1)+(y²-1)=0

  y=-3

  2,1/(x-3)-1/(x-4)=1/(x-6)-1/(x-7)

  1/(x-3)+1/(x-7)=1/(x-4)+1/(x-6)

  (2x-10)/(x²-10x+21)=(2x-10)/(x²-10x+24)

  因为x²-10x+21≠x²-10x+24,

  所以,2x-10=0,x=5.
  0 讨论(0)
  发布评论:

  提交评论

  ---

  •  加载中...