f(x)=2^x-(1/2)^x=2^x-2^(-x)f(log2/3)=2^(log2/3)-2^(-log2/3)=3+3=6f(x)=2^x-2^(-x)=2两边取对数,得log2/(2^x)-log2/[2^(-x)]=log2/2即,x+x=1故x=1/2